Question 1012843
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Sine theta = cos(2 theta-10)
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{{{sin(theta)}}} = {{{cos(2*theta-10)}}}.   (1)

I don't know exactly what is 10: radians or degrees? Will suppose degrees.

We all know that

{{{sin(theta)))}}} = {{{cos(90^o-theta)}}}.

Combining this with (1), you will get

{{{cos(2*theta-10^o)}}} = {{{cos(90^o-theta)}}}.

It implies that 

{{{2*theta-10^o}}} = {{{90^o-theta}}}.   (2)

Not exactly, because you should remember about +/-{{{2k*pi}}} and other similar additional terms, 
but I am going to give only the "naive" solution here.

From (2) you have

{{{3*theta}}} = 90° +10° = 100°.   Hence {{{theta}}} = {{{1/3}}}.100°.
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