Question 1012913
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The given line and the two axes form a right triangle with the right angle at the origin.  The absolute value of the *[tex \Large x]-coordinate of the *[tex \Large x]-intercept is equal to the measure of one of the legs of the triangle.  The absolute value of the *[tex \Large y]-coordinate of the *[tex \Large y]-intercept is equal to the measure of the other leg of the triangle.  The product of the measures of the two legs of a right triangle divided by 2 is the area of the triangle.


Step 1:  Substitute 0 for *[tex \Large y] in the given equation and solve for *[tex \Large x].  This is the *[tex \Large x]-coordinate of the *[tex \Large x]-intercept.  Take the absolute value of this value.


Step 2:  Substitute 0 for *[tex \Large x] in the given equation and solve for *[tex \Large y].  This is the *[tex \Large y]-coordinate of the *[tex \Large y]-intercept.  Take the absolute value of this value.


Step 3:  Multiply the result of step 1 times the result of step 2.  Divide this product by 2.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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