Question 1012886
The five terms are a, a+d, a+2d, a+3d and a+4d.
If we add them we get
5a + 10d = 115  or
a + 2d = 23 or
a = 23 - 2d
We also have
(a+d)^2 + (a+3d)^2 = 1156
We can substitute from before into this and get
(23 - 2d + d)^2 + (23 - 2d + 3d)^2 = 1156
(23 - d)^2 + (23 + d)^2 = 1156
529 - 46d + d^2 + 529 + 46d + d^2 = 1156
2d^2 + 1058 = 1156
2d^2 = 98
d^2 = 49
d = 7, -7
a is then 23 - 2(7) = 9 or 23 - 2(-7) = 37
Thus our two possibilities appear to be
9, 16, 23, 30, 37  and
37, 30, 23, 16, 9