<PRE><B>Question 1012873</B>
 If the volume of a cone is decreased by 20% and the height increased by 10%. How is the radius affected? 
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Volume Formula: V = (1/3)pi*r^2*h
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Modified:: 0.9V = (1/3)*pi*r^2*(1.1h)
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Solve for &quot;r&quot;::
r^2 = 2.7/[pi*1.1h]
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r = sqrt[(2.7/1.1)*pi*h]
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Cheers,
Stan H.
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