<PRE><B>Question 1012864</B>
Please help me solve this : 
In an geometric progression , b1=3 and b2=6 
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a = 3
ar = 6
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ar/a = 6/3
r = 2
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Solve b2015 = ar^(2014) = 3*2^2014
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Cheers,
Stan H.
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