Question 1012731
4 members of a family 10 years ago, the average age was 24 years old 
| 2 Children born after the family still has the same average age 
| Assuming that the child is under the age of 2 years, the difference
| The current age of the children, find?
:
The present ages of the four original members of the family, a,b,c,d
The two children born later; e & f
Let f < 2 yrs, as it says
therefore
f = 1 yr old
:
Av 10 yrs ago
{{{((a-10) + (b-10) + (c-10) + (d-10))/4 = 24}}}
multiply both sides by 4, simplify
a + b + c + d - 40 = 96
a + b + c + d = 96 + 40
a + b + c + d = 136, their total age now
:
Therefore we can write the equation including the two late born children
{{{(136 + e + f )/6}}} = 24
multiply both sides by 6
136 + e + f = 144
e + f = 144 - 136
e + f = 8 yrs
we know that f is 1 yr old
e + 1 = 8
e = 7 yrs old
:
the difference: 6 yrs in the last two children
| The current age of the children, ages 7 and 1