Question 1012742
Call the amount of 80% acid used, x.
Then the amount of 30% acid used would be 150-x.
The setup looks like this:
(.80)x + (.30)(150-x) = (.62)(150)
Now solve this for x...
.8x + 45 - .3x = 93
.5x = 48
x = 96 L of 80% acid
Then 150 - x = 54 L of 30% acid