Question 1012688
{{{-3<0}}} so,
{{{f(-3)=3(-3)+3=-9+3=-6}}}
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The function is only defined when {{{x<0}}} and {{{x>0}}} so {{{f(0)}}} is undefined. 
If you wrote it down incorrectly, then plug {{{x=0}}} into whichever function is the correct function.
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{{{2>0}}} so,
{{{f(2)=2(2)+5=4+5=9}}}