Question 1008373
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N=1 peso coins; F=5 peso coins=N T=10 peso coins
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N+F+T=20
N+N+T=20
T=20-2N
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(1)N+5(F)+10(T)=88
N+5(N)+10(20-2N)=88
6N+200-20N=88
-14N=-112
N=8
ANSWER 1: There are eight 1 peso coins.
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F=N=8
ANSWER 2: There are eight 5 peso coins.
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T=20-2N=20-2(8)=20-16=4
ANSWER 3: There are four 10 peso coins.
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CHECK:
1(N)+5(F)+10(T)=88
1(8)+5(8)+10(4)=88
8+40+40=88
88=88
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