Question 1012561
Call the width of the path, x.
Then the dimensions of the pool and path will be
(18+x) by (22+x)
We can multiply them, set it equal to 1152 and solve for x...we get
(x+18)(x+22) = 1152
x^2 + 40x + 396 = 1152
x^2 + 40x - 756 = 0
(x + 54)(x - 14) = 0
x = -54  or x = 14
Must be 14 meters.