Question 1012536
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at 9 am, Mark and Tom get on their motor bikes to meet each other from towns located 45 km apart. 
Mark travels 5 km/h faster than Tom. At what must each travel if they were to meet at 10:12 am?
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<pre>
Let x be Mark' speed in {{{km/h}}}. Then tom' speed is x-5 {{{km/h}}}

Since they move toward each other, the rate of decreasing the distance between them is x + (x-5) = 2x-5 {{{km/h}}}.

The time they spent for their trip is 1 hour 12 minutes, or {{{6/5}}} of an hour.

Your equation is Time = {{{Distance/Rate}}},   or

{{{6/5}}} = {{{45/(2x-5)}}}.

To solve it, multiply both sides by 2x-5. You will get

6*(2x-5) = 5*45,   or

12x - 30 = 225,

12x = 225 + 30 = 255.

x = {{{255/12}}} {{{km/h}}} = 21.25 {{{km/h}}}.
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