<PRE><B>Question 1012550</B>
find area of the triangle constructed by the lines5x+7y=35,4x+3y=12and x axis
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Find the intersection of the 2 lines.

5x+7y=35
4x+3y=12
The y value of the intersection is 80/13
Since the other 2 vertices are on the x-axis, 80/13 is the height of the triangle.
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Find the intersections of the lines and the x-axis
5x + 7y = 35
@y = 0; x = 7
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4x + 3y = 12
@y = 0; x = 3
The base = 7-3 = 4
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Area = b*h/2 = (80/13)*4/2
Area = 160/13 sq units</PRE>