Question 1012489
the vertex angle of an isosceles triangle is twice as large as one of the base angles. Find the measure of the vertex angles.
<pre>Let measure of vertex angle, be V
Then each congruent base angle = {{{(1/2)V}}}, or {{{V/2}}}
The angles of a triangle sum to {{{180^o}}}, and so, we get: {{{V + 2(V/2) = 180}}}
V + V = 180
2V = 180
V, or vertex angle measures: {{{180/2}}}, or {{{highlight_green(90^o)}}}