Question 1012451
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Not using Lopital's rule, how can i solve lim,x->0 ln(e-7x)-1
Can i separate ln(e-7x) on lne - or / ln7 somehow? 
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If it is {{{ln(e-7x)-1}}}   (literally as it is written), then the limit at x-->0 is {{{ln(e) - 1}}} = 1 - 1 = 0.

If it is something else, then please use parentheses to write it correctly.
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