Question 1012470
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The sum of the squares of two consecutive integers is 9 greater than 8 times the smaller integer. Find the integers
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{{{x^2 + (x+1)^2}}} = {{{8x + 9}}},

{{{x^2 + x^2 + 2x + 1}}} = {{{8x + 9}}},

{{{2x^2 -6x -8}}} = {{{0}}},

Use the quadratic formula to solve this quadratic equation.

You will get two solutions: x = -1 and x = 4.

<U>Answer</U>. There are two solutions: x = -1 and x = 4.
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