Question 1012392
Perpendicular lines have slopes that are negative reciprocals.
{{{4*m[p]=-1}}}
{{{m[p]=-1/4}}}
So using the point-slope form,
{{{y-3=-(1/4)(x-8)}}}
{{{y-3=-(1/4)x+2}}}
{{{y[p]=-(1/4)x+5}}}