Question 1012368
f(x) = {{{x^5}}}


when x = 2, you replace x with 2 to get f(2) = {{{2^5}}} = 32


when x = -1, you replace x with -1 to get f(-1) = {{{(-1)^5}}}= -1


g(x) = {{{1/(x+1)}}}


when x = 0, you replace x with 0 to get g(0) = {{{1/(0+1)}}} = 1/1 = 1


f(x) = {{{x^5}}}


g(x) = {{{1/(x+1)}}}


f(g(x)) means you replace x with g(x) to get f(g(x)) = {{{(g(x))^5}}}.


since g(x) = {{{1/(x+1)}}}, then you replace g(x) with {{{1/(x+1)}}} to get f(g(x)) = {{{(1/(x+1))^5}}}.


therefore f(g(x)) = {{{(1/(x+1))^5}}} when f(x) = {{{x^5}}} and g(x) = {{{1/(x+1)}}}.


g(f(x)) means you replace x with f(x) to get g(f(x)) = {{{1/(f(x)+1)}}}.


since f(x) = {{{x^5}}}, then you replace f(x) with {{{x^5}}} to get g(f(x)) = {{{1/(x^5+1)}}}.


therefore g(f(x)) = {{{1/(x^5+1)}}} when g(x) = {{{1/(x+1)}}} and f(x) = {{{x^5}}}.