Question 1012349
{{{(x + 3/x )^2 = 16}}}


{{{x+3/x=0+- 4}}}
{{{x(x+3/x)=0+- 4x}}}
{{{x^2+3=0+- 4x}}}
{{{x^2-4x+3=0}}}  OR  {{{x^2+4x+3=0}}}



First form,
{{{(x-1)(x-3)=0}}}
{{{x=1}}} OR {{{x=3}}}


Second form,
{{{(x+1)(x+3)=0}}}
{{{x=-1}}}  OR  {{{x=-3}}}


x can be any one of  -1 or -3  or 1  or  3.