Question 1012326
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solve the equation on the interval [0,2pi): tan x/2=-sqrt 3/3
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{{{tan(x/2)}}} = -{{{sqrt(3)/3}}}  ----->

{{{x/2}}} = {{{(5pi)/6}}} or/and {{{x/2}}} = {{{(11pi)/6}}}.


If {{{x/2}}} = {{{(5*pi)/6}}}, then x = {{{5pi/3}}}. It is one solution.


If {{{x/2}}} = {{{(11*pi)/6}}}, then x = {{{11pi/3}}}. It is greater than {{{2pi}}}, and you need to reduce it to the reference angle, which is {{{5pi/3}}}.

Thus the problem has a unique solution x = {{{5pi/3}}}.
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