Question 1012209
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Find the value of log3.6 given that log2 is equal to 0.3010, 
log3 is equal to 0.4771 and log5 is equal to 0.6990
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3.6 = {{{(2*9)/5}}} = {{{(2*3^2)/5}}}.


Therefore, {{{log((3.6))}}} = {{{log((2)) + 2*log((3)) - log((5))}}} = 0.3010 +2*0.4771 - 0.6990 = 0.5562.