Question 1012194
Hi, I'm having trouble with the problem h(x) = -16x^2 + 64x + 140 where h(x) equals the height. I'm trying to find the height, but I'm not sure how to. When asked to write the quadratic function in vertex form I came up with f(x) = 16(x+2)^2-56.

Thanks.
<pre>The height is represented by the y-coordinate of the VERTEX
The height, or y-coordinate of the VERTEX, or h(x) occurs at: {{{x = - b/2a}}} -----> {{{x = - 64/(2 * - 16)}}} ------> {{{x = (- 64)/(- 32)}}} ------> x = 2
{{{h(x) = - 16x^2 + 64x + 140}}} 
{{{h(2) = - 16(2)^2 + 64(2) + 140}}} ------- Substituting 2 for x
{{{h(2) = - 16(4) + 64(2) + 140}}}
{{{h(2) = - 64 + 128 + 140}}}
{{{h(2) = 204}}}
The height, or y-coordinate of the VERTEX occurs at h(2), and is:{{{highlight_green(204)}}}
It is that simple!
If you NEED to write the quad function in VERTEX form, then that's another story, but you don't have to!