Question 1012194
{{{h(x) = -16x^2 + 64x + 140}}} in vertex form

{{{h(x) = (-16x^2 + 64x+b^2)-b^2 + 140}}}

{{{h(x) = -16(x^2 -4x-b^2)-16(-b^2) + 140}}}

{{{h(x) = -16(x^2 -4x-2^2)+16*2^2 + 140}}}

{{{h(x) = -16(x -2)^2+64 + 140}}}

{{{h(x) = -16(x -2)^2+204}}}


vertex is at:

({{{2}}}, {{{204}}})


{{{drawing( 600, 600, -10, 10, -10, 250,
circle(2,204,.125),locate(2,204,V(2,204)),
 graph( 600, 600, -10, 10, -10, 250, -16(x -2)^2+204)) }}}