Question 1012193
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find the length of the shortest side of a triangle whose perimeter is 66 and the sides are marked as x+5, 3X-1 AND 4X-2 what is the shortest side
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Your equation is 

(x+5) + (3x-1) + (4x-2) = 66.

8x + (5-1-2) = 66,

8x + 2 = 66,

8x = 66 - 2 = 64,

x = 8.

The sides of the triangle are:

side 1:  x + 5 = 8+5      = 13;
side 2:  3x-1  = 3*8-1    = 23;
side 3:  4x - 2 = 4*8 - 2 = 30,

The shortest side is 13.
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