Question 1012131

Please help me with this item.  
f(x) = 3x ^-1
g(x) = 2x-7
h(x) =(x+4)/3

What is h(f(x))

I don't quite get the book answer of 1/x+4/3

Thank you in advance.
<pre>{{{f(x) = 3x ^-1}}}
{{{g(x) = 2x-7}}} (Not Relevant to this problem)
{{{h(x) =(x + 4)/3}}}
{{{h(f(x)) = h(3x^(- 1)) = (3x^(- 1) + 4)/3}}} ----> {{{(3 * (1/x) + 4)/3}}} ----> {{{(3/x + 4)/3}}} ----> {{{(3/x + 4)}}}{{{"÷"}}}{{{3/1}}} ------> {{{(3 + 4x)/x}}}{{{"÷"}}}{{{3/1}}} -----> {{{(3 + 4x)/x}}}{{{"*"}}}{{{1/3}}} ------> {{{(3 + 4x)/(3x)}}}, or {{{3/(3x) + 4x/(3x)}}}, or {{{highlight_green(1/x + 4/3)}}}