Question 1012110
Lets say the bigger number is y, and the smaller number is x. If they're consecutive, then y=x+1.
Three times the smaller one is 3x, added to twice to the bigger one is 2y. They add to 27, to get the equation {{{3x+2y=27}}}
We use substitution y=x+1 to get {{{3x+2(x+1)=27}}} and solve.
{{{3x+2x+2=27}}}
{{{5x=25}}}
{{{x=5}}
{{{y=(5)+1}}}
{{{y=6}}}