Question 1012074
In general {{{log(ab)=log(a)+log(b)}}} and {{{log(a^b)=b*log(a)}}}.
So, {{{log(10^3)+log(10^5)=3log(10)+5log(10)}}}. {{{8log(10)=log(10^8)}}}, therefore, {{{log(10^3)+log(10^5)=log(10^8)}}}


The two equations are related because the additions of logarithms produces the same operation as multiplication with regular numbers. Moreover, the conversion is also able to be done, to get the same result on both equation just by taking log/exponentiation, showing that the two are inverses.