<PRE><B>Question 1011955</B>
find three consecutive integers such that twice the smallest plus three times the middle is equal to twenty-two less than six times the largest 
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1st: x-1
2nd: x
3rd: x+1
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Equation:
2(x-1) + 3x = 6(x+1)-22
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2x - 2 + 3x = 6x + 6 - 22
5x -2 = 6x - 16
x = 14
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x-1 = 13
x = 14
x+1 = 15
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Cheers,
Stan H.</PRE>