Question 1011908

Theorem:  An measure of an exterior angle of a triangle is equal to the sum of the measures of the two non-adjacent interior angles.

if the measure of  angle {{{highlight(alpha=68)}}} (at vertices A), 

and if the measure of an exterior angle of a triangle is {{{116}}}

if  that  exterior angle is at vertices B, then it is supplementary angle to angle {{{beta}}};

so, {{{beta+116=180}}}=>{{{beta=180-116}}}=>{{{highlight(beta=64)}}}

then

{{{alpha+beta+gamma=180}}}

{{{68+64+gamma=180}}}

{{{gamma=180-(68+64)}}}

{{{gamma=180-132}}}

{{{highlight(gamma=48)}}}