Question 1011839
the perimeter of a triangle is 79.75 inches. the second side of the triangle is half as big as the first side the third side is 7.25 inches greater than the first side. what is the length of the longest side of the triangle. give your answer as a decimal 
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Let the sides be a,b,c
Equations:
a + b + c = 79.75
b = a/2
c = a + 7.25
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Substitute and solve for "a":
a + a/2 + a + 7.25 = 79.75
(5/2)a = 72.50
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a = 145/5
a = 29 inches
b = 14.5 inches
c = 36.25 inches
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Cheers,
Stan H.
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