Question 1011843
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xy=12, (x^2+y^2)=25 then what is the value of (x+y)2^2 ?
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xy=12, {{{x^2+y^2}}} = {{{25}}} implies that

{{{x^2 + 2xy + y^2}}} = {{{x^2+y^2}}} + {{{2xy}}} = 25 + 2*12 = 25 + 24 = 49.

Again:

{{{(x+y)^2}}} = {{{x^2 + 2xy + y^2}}} = 49.

So, if you need {{{(x+y)^2}}}, you just have it: it is 49.

What you do REALLY need, I don't know, because you do neglect to use parentheses properly.

If it is {{{((x+y)*2)^2}}}, then it is equal to 4*49.
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