Question 1011765
Demand:
When {{{p=12}}}, {{{q=600}}}.
When {{{p=13}}}, {{{q=600-50=550}}}.
So then the slope is,
{{{m[d]=(550-600)/(13-12)=-50}}}
Using the point-slope form of a line,
{{{q-600=-50(p-12)}}}
{{{q-600=-50p+600}}}
{{{q=-50p+1200}}}
.
.
.
Supply:
When {{{p=9.75}}}, {{{q=600-210=390}}}
When {{{p=10.75}}}, {{{q=390+40=430}}}
So then the slope is,
{{{m[s]=(430-390)/(10.75-9.75)=40/1=40}}}
And similarly,
{{{q-390=40(p-9.75)}}}
{{{q-390=40p-390}}}
{{{q=40p}}}