Question 1011816
The given product is a multiple of 2 because the ONES digit is even and is itself 2.


The only way to have sum of two prime numbers to be 19 is they are 2 and 17.
The other composite part will be  {{{4522/(2*17)=133}}}.


Factorize 133.  This will(or CAN) include prime numbers LESS than {{{sqrt(133)}}}.  This allows narrowing the choices to look for.  No longer being even, therefore no longer divisible by 2, the choices are  3, 5, 7, 11.
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You can omit 3 and 5 from this listing.  No ending in 5 and adding value of digits does not give multiple of 3.


133-11=122  No good.
133/7=19------------two prime numbers,  7 and 19.


RESULT:   2, 7, 17, 19.