Question 1011801

use trigonometry

{{{sin(45)=6sqrt(5)/x}}}

{{{x=6sqrt(5)/sin(45)}}}

{{{x=6sqrt(5)/(1/sqrt(2))}}}

{{{x=6sqrt(5)*sqrt(2)}}}

{{{x=6sqrt(10)}}}

approximately

{{{x=18.97}}} or {{{x=19}}}