Question 1011757
The altitude to the base of an isosceles triangle bisects the vertex angle.

Given:KA is an altitude of Triangle KZJ, A is the midpoint of ZJ.
Prove: Triangle KAJ = KAZ

S1:KA is an altitude of Triangle KZJ- Given
S2: A is the midpoint of ZJ- Given
S3: KA = KA - Reflexive Property.(common side)
S4 ZA=AJ....The altitude to the base of an isosceles triangle bisects the base
S5 < KJA = < KZA - as angles across same side KA 
S6- Triangle KJA = Triangle KZA - SAS