Question 1011754
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what is the shortest side of a triangle with a perimeter of 66 and x+5, 3x-1 and 4x-2 it does not label the sides all it ask is for the shortest side
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Let us find x first. The sum of the lengths of the sides of the triangle is 


(x+5) + (3x-1) + (4x-2) = 8x + 2.


It is equal to 66:


8x + 2 = 66.


Hence, x = {{{(66-2)/8}}} = {{{64/8}}} = 8.


Now calculate each side length and compare.