Question 1011734
log(x)+log(y)=log(x*y) so:
log(X)+log(X-7)=log(X+11)+log(2)
log[(X)(X-7)]=log[(X+11)(2)] Taking anti-logs:
(X)(X-7)=(X+11)(2)
.
{{{X^2-7X=2X+22}}}
{{{X^2-9X-22=0}}}
{{{(X-11)(X+2)=0}}}
{{{X-11=0}}} {{{OR}}} {{{X+2=0}}}
{{{X=11}}} {{{OR}}} {{{X=-2}}}