Question 1011696
{{{log((x))+log((x-4))=6}}}
{{{log((x(x-4)))=6}}}
{{{log((x^2-4x))=6}}}
{{{b^6=x^2-4x}}}
{{{x^2-4x-b^6=0}}}
-
Going further - apply formula for general solution of a quadratic equation,
{{{x=(4+- sqrt(16-4*b^6))/2}}}
and simplify to 
{{{highlight_green(x=2+- sqrt(4+b^6))}}}.


Anything further depends on knowing the base b.


WHAT BASE FOR THE LOGARITHM?