Question 86723
See here we have well shuffled 52 card deck and we have to drawn one single card .There are 13 clubs in 52 card deck. we know that let a space of elementary events  E  be given and this space consists of  N  equally likely elementary events, among which there are  n  events, favorable for an event  A. Then the number

 

                                                                                  Р ( А ) = n / N

 

is called the probability of an event  A .

 
here n = 13( from 13 clubs we have to pick 1 club)
and N= 52 ( from 52 cards we are picking 1 )
required probability = 13/52 = 1/4(Answer)


Each of ten tickets is marked with a different number from 1-10 and put in a box. If you draw a ticket at random from the box, what is the probability that you will draw 4,8,or 6? 

See here n=3 (4 or 8 or 6, from these 3 we are picking 1)
and N = 10(total no. of 10 tickets we are picking 1)

so reqd probability = 3/10(Answer)


from an ordinary deck of 52 playing cards. 
Letting:
A = event a queen is selected
B = event a diamond is selected

Here reqd probability = 4/52=1/13
total no. of queen =4 
and total no. of diamond = 13
so reqd probability = 13/52 = 1/4