Question 1011602
The sum of two distinct numbers is 26. If the smaller number is reduced by 1 and the larger number by 3, the product of the two resulting number is 120. What are the numbers? 
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Equations:
S + L = 26
(S-1)(L-3) = 120
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Substitute for "S" and solve for "L"::
(26-L-1)(L-3) = 120
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(25-L)(L-3) = 120
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-L^2 + 28L - 75 = 120
L^2 - 28L + 195 = 0
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L = 15
S = 11
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Cheers,
Stan H.
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