Question 1011590
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Find the equation of the locus of a point p (x,y) when:

1. the distance of P from the line y=-5 is three quarters of its distance from the line x = 2

2. The distance of P from the line  x= -3 is two fifths of its distance from the line y= -1
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1. The locus for #1 is the straight line passing through the point (x,y) = (2,-5) and having the slope {{{3/4}}}:
   y + 5 = {{{3/4}}}.(x-2),    or    y = 0.75x - {{{3/2}}} - 5,   or   y = 0.75 - 6.5.

   Make a sketch. Draw the coordinate axes. Draw the line x = 2 and the line y = -5. Then draw your line.


2. Try to do it by analogy with the #1.

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Comment from student: When i tried to do the second question, i could not achieve the answer. Can u show me step by step explanation??
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OK, let's do it.

2. The locus for #2 is the straight line passing through the point (x,y) = (-3,-1) and having the slope {{{5/2}}}:
   y + 1 = {{{5/2}}}.(x+3),    or    y = {{{5/2}}}x + {{{15/2}}} - 1,   or   y = {{{5/2}}}x + 6.5.

   Make a sketch. Draw the coordinate axes. Draw the line x =-3 and the line y = -1. Then draw your line. 
   Put the point P on the line. Then mark those distances dx and dy. Then think.
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