Question 1011590
The two questions are very much alike.  Question number 1 gives the horizontal line y=-5 and the vertical line x=2; these are the more general points  (x,-5) and (2,y).  Fit the description into the Distance Formula:


{{{sqrt((x-x)^2+(y-(-5))^2)=(3/4)sqrt((x-2)^2+(y-y)^2)}}}


{{{sqrt((y+5)^2)=(3/4)sqrt((x-2)^2)}}}


{{{y+5=0+- (3/4)(x-2)}}}


Simplify into the two equations in whatever form you want.
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{{{y+5=-(3/4)(x-2)}}}
{{{y=-(3/4)x+3/2-5}}}
{{{highlight(y=-(3/4)x-7/2)}}}------one of the lines
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{{{y+5=(3/4)(x-2)}}}
{{{y+5=(3/4)x-3/2}}}
{{{y=(3/4)x-3/2-10/2}}}
{{{highlight(y=(3/4)x-13/2)}}}-----------other line