Question 1011581

 From your question we can obtain the relation
{{{10x+y=4(x+y)}}}
{{{10x+y=4x+4y}}}
{{{6x-3y=0}}}
{{{x=(1/2)y}}}

{{{x}}} and {{{y}}} must be {{{single}}} digit numbers.Further {{{y}}} must be {{{even}}} so that {{{x}}} can be a {{{whole}}} number.
Hence {{{y}}}={{{2}}},{{{4}}},{{{6}}},or {{{8}}} => {{{x}}}={{{1}}},{{{2}}},{{{3}}},or {{{4}}}
The numbers are {{{12}}},{{{24}}},{{{36}}},{{{48}}}.