Question 12293
{{{7*root(3,48x^4y^8) / root(3,6y^2)}}}
{{{7*root(3,(48x^4y^8)/(6y^2))}}}
{{{7*root(3,(8x^4y^6))}}}


now, since 2*2*2 is 8
and  since {{{y^2*y^2*y^2}}} is {{{y^6}}} then


{{{7*2*y^2*root(3,(x^4))}}}


jon.