Question 86694
Find three consecutive even integers such that the product of the first integer and the third integer is equal to four less than ten times the second integer.
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Comment: Even numbers are always multiples of 2
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1st number: 2x
2nd number: 2x+2
3rd number: 2x+4
EQUATION:
(2x)(2x+4)=10(2x+2)-4
Divide thru by 4 to get:
x(x+2) = 5(x+1)-1
x^2+2x = 5x+4
x^2-3x-4=0
(x-4)(x+1)=0
Positive answer:
x=4
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1st number : 2x = 8
2nd number : 10
3rd number : 12
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Cheers,
Stan H.