Question 1011453
a.  Point estimate is the mean of the data: 98.7 F.
b.  99%CI is 2.576*SE.  The SE is s/sqrt(n)=0.64/sqrt(105)=0.0625
The half interval is 2.576*0.0625=0.1609 (no rounding until the end)
The 99% CI is (98.54,98.86)deg F are units.
The limits do not contain 98. They do contain 98.6 F.
Because 98.6 is in the interval, 98.6 F is a plausible temperature for the body.  Anything in the interval is a plausible temperature.  We do not and never will know the exact temperature, but we can be highly confident that the temperature will lie in the interval we constructed.  
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The mean body temperature could be lower than 98.6 F., but not lower than 98.54 F.
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The mean body temperature could be higher than 98.6,F. as high as 98.88 F.
Confidence intervals are not probability.  A CI is a way to define a range in which the unknown parameter is likely to be found.  It either is in the interval or not, and that is not a probability question.  Stated another way, if we took 100 different samples of the same size and made 100 CI, 99 of them would contain the parameter.  We just wouldn't know which 99.  A CI is the z, t, or other value multiplied by the standard error of the mean.  Wider intervals have high confidence, which makes sense.  A 100% CI would contain everything,