Question 1011338
the smallest possible value a quadratic in the form of ax^2 + bx + c = 0 would be at x = -b/2a.


your equation of x^2 -8x + 25 is already in that form when you set it equal to 0.


a = coefficient of x^2 term = 1
b = coefficient of x term = -8
c = coefficient of c term = 25


x = -b/2a = -(-8)/(2*1) = 8/2 = 4


when x = 4, y = x^2 - 8x + 25 becomes y = 4^2 - 8*4 + 25 which becomes 16 - 32 + 25 which becomes 9.


the smallest value of x^2-8x+25 would be equal to 9.


here's what the graph looks like.


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