Question 1011250
{{{(-5+i)/(2i)}}}

={{{i(-5+i)/(2i*i)}}}

={{{(-5i+i^2)/(2i^2)}}}

={{{(-5i-1)/(2(-1))}}}

={{{(-5i-1)/(-2)}}}

={{{-5i/-2-1/-2}}}

={{{5i/2+1/2}}}

={{{1/2+5i/2}}}