Question 86683
5x + 7y = b--------------eq1
mx+ y = 22----------------eq2

Since we want the solution to this system of equations to be (-3,4), we substitute (-3,4) into each equation and solve for the unknowns.

From eq1
5*(-3)+7*4=b

b=-15+28

b=13


From eq2

-3m+4=22

-3m=22-4

-3m=18

m=-6

So---


5x+7y=13-------------------Final eq1
-6x+y=22-------------------------Final eq2

CK

Substitute (-3,4) into eq 1

-15+28=13
13=13------ok

Substitute (-3,4) into eq2

-6(-3)+4=22

18+4=22

22=22-------ok


Hope this helps---ptaylor