Question 1011190
the 95% confidence for tdf+48 is 2.01, the std error is s/sqrt(n)=1.9/7
the half limit is 2.01*s/sqrt(n)=2.01*1.9/7=0.5456
The 95% CI has an upper limit of 50.5456 or 50.55 min.
The 99% CI has a t of 2.68.
2.68*1.9/7=0.7274
(49.2726,50.7274) min.