Question 1011230
Exactly 3
12C3*(.38^3)*(.62^9)=0.1634  ANSWER TO A
Exactly 2=12C2(0.38^2)(0.62^10)=0.0800
Exactly 1=12*0.38*0.62^11=0.0237
0=0.62^12=0.0032
At least 4 is 1-the probability of 0,1,2,3=1-0.2703=0..7297
at most 2 is P(2,1,0)=0.1069.
As a side note the expected value if 12*0.38=4.56, so 4 and 5 will be a large portion of the probability.  This serves as a check for "at least 4".